-2(y-2)=2y-12

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Solution for -2(y-2)=2y-12 equation: 



-2(y-2)=2y-12

We move all terms to the left:

-2(y-2)-(2y-12)=0

We multiply parentheses

-2y-(2y-12)+4=0

We get rid of parentheses

-2y-2y+12+4=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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