-2(y+2)=7y-4+2(3y+9)

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Solution for -2(y+2)=7y-4+2(3y+9) equation: 



-2(y+2)=7y-4+2(3y+9)

We move all terms to the left:

-2(y+2)-(7y-4+2(3y+9))=0

We multiply parentheses

-2y-(7y-4+2(3y+9))-4=0



We calculate terms in parentheses: -(7y-4+2(3y+9)), so:

7y-4+2(3y+9)

determiningTheFunctionDomain
7y+2(3y+9)-4

We multiply parentheses

7y+6y+18-4

We add all the numbers together, and all the variables

13y+14

Back to the equation:

-(13y+14)



We get rid of parentheses

-2y-13y-14-4=0

We add all the numbers together, and all the variables

-15y-18=0

We move all terms containing y to the left, all other terms to the right

-15y=18

y=18/-15

y=-1+1/5

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