2(v-3)-5=-3(-8v+1)-8v

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Solution for 2(v-3)-5=-3(-8v+1)-8v equation: 



2(v-3)-5=-3(-8v+1)-8v

We move all terms to the left:

2(v-3)-5-(-3(-8v+1)-8v)=0

We multiply parentheses

2v-(-3(-8v+1)-8v)-6-5=0



We calculate terms in parentheses: -(-3(-8v+1)-8v), so:

-3(-8v+1)-8v

We add all the numbers together, and all the variables

-8v-3(-8v+1)

We multiply parentheses

-8v+24v-3

We add all the numbers together, and all the variables

16v-3

Back to the equation:

-(16v-3)



We add all the numbers together, and all the variables

2v-(16v-3)-11=0

We get rid of parentheses

2v-16v+3-11=0

We add all the numbers together, and all the variables

-14v-8=0

We move all terms containing v to the left, all other terms to the right

-14v=8

v=8/-14

v=-4/7

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