5(3-2x)=4(1-3x)

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Solution for 5(3-2x)=4(1-3x) equation: 



5(3-2x)=4(1-3x)

We move all terms to the left:

5(3-2x)-(4(1-3x))=0

We add all the numbers together, and all the variables

5(-2x+3)-(4(-3x+1))=0

We multiply parentheses

-10x-(4(-3x+1))+15=0



We calculate terms in parentheses: -(4(-3x+1)), so:

4(-3x+1)

We multiply parentheses

-12x+4

Back to the equation:

-(-12x+4)



We get rid of parentheses

-10x+12x-4+15=0

We add all the numbers together, and all the variables

2x+11=0

We move all terms containing x to the left, all other terms to the right

2x=-11

x=-11/2

x=-5+1/2

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