-2(y+2)=4y-4+2(2y+8)

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Solution for -2(y+2)=4y-4+2(2y+8) equation: 



-2(y+2)=4y-4+2(2y+8)

We move all terms to the left:

-2(y+2)-(4y-4+2(2y+8))=0

We multiply parentheses

-2y-(4y-4+2(2y+8))-4=0



We calculate terms in parentheses: -(4y-4+2(2y+8)), so:

4y-4+2(2y+8)

determiningTheFunctionDomain
4y+2(2y+8)-4

We multiply parentheses

4y+4y+16-4

We add all the numbers together, and all the variables

8y+12

Back to the equation:

-(8y+12)



We get rid of parentheses

-2y-8y-12-4=0

We add all the numbers together, and all the variables

-10y-16=0

We move all terms containing y to the left, all other terms to the right

-10y=16

y=16/-10

y=-1+3/5

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