9=1/3(h-2)

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Solution for 9=1/3(h-2) equation: 



9=1/3(h-2)

We move all terms to the left:

9-(1/3(h-2))=0



Domain of the equation: 3(h-2))!=0

h∈R



We multiply all the terms by the denominator


-(1+9*3(h-2))=0



We calculate terms in parentheses: -(1+9*3(h-2)), so:

1+9*3(h-2)

determiningTheFunctionDomain
9*3(h-2)+1

Wy multiply elements

27h(h+1

Back to the equation:

-(27h(h+1)





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27h(h+1





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27h(h+1





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27h(h+1





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27h(h+1





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27h(h+1





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