9+2(2v-3)=-3(6v-4)+7v

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Solution for 9+2(2v-3)=-3(6v-4)+7v equation:



9+2(2v-3)=-3(6v-4)+7v
We move all terms to the left:
9+2(2v-3)-(-3(6v-4)+7v)=0
We multiply parentheses
4v-(-3(6v-4)+7v)-6+9=0
We calculate terms in parentheses: -(-3(6v-4)+7v), so:
-3(6v-4)+7v
We add all the numbers together, and all the variables
7v-3(6v-4)
We multiply parentheses
7v-18v+12
We add all the numbers together, and all the variables
-11v+12
Back to the equation:
-(-11v+12)
We add all the numbers together, and all the variables
4v-(-11v+12)+3=0
We get rid of parentheses
4v+11v-12+3=0
We add all the numbers together, and all the variables
15v-9=0
We move all terms containing v to the left, all other terms to the right
15v=9
v=9/15
v=3/5

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