-2(b-4)=3(b+4)+1

Solution for -2(b-4)=3(b+4)+1 equation:

-2(b-4)=3(b+4)+1

We move all terms to the left:

-2(b-4)-(3(b+4)+1)=0

We multiply parentheses

-2b-(3(b+4)+1)+8=0


We calculate terms in parentheses: -(3(b+4)+1), so:

3(b+4)+1

We multiply parentheses

3b+12+1

We add all the numbers together, and all the variables

3b+13

Back to the equation:

-(3b+13)


We get rid of parentheses

-2b-3b-13+8=0

We add all the numbers together, and all the variables

-5b-5=0

We move all terms containing b to the left, all other terms to the right

-5b=5

b=5/-5

b=-1