2(2x-4)-2=(x+3)+8

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Solution for 2(2x-4)-2=(x+3)+8 equation:



2(2x-4)-2=(x+3)+8
We move all terms to the left:
2(2x-4)-2-((x+3)+8)=0
We multiply parentheses
4x-((x+3)+8)-8-2=0
We calculate terms in parentheses: -((x+3)+8), so:
(x+3)+8
We get rid of parentheses
x+3+8
We add all the numbers together, and all the variables
x+11
Back to the equation:
-(x+11)
We add all the numbers together, and all the variables
4x-(x+11)-10=0
We get rid of parentheses
4x-x-11-10=0
We add all the numbers together, and all the variables
3x-21=0
We move all terms containing x to the left, all other terms to the right
3x=21
x=21/3
x=7

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