-2(4w-2)+8w=1+5(2w-1)

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Solution for -2(4w-2)+8w=1+5(2w-1) equation: 



-2(4w-2)+8w=1+5(2w-1)

We move all terms to the left:

-2(4w-2)+8w-(1+5(2w-1))=0

We add all the numbers together, and all the variables

8w-2(4w-2)-(1+5(2w-1))=0

We multiply parentheses

8w-8w-(1+5(2w-1))+4=0



We calculate terms in parentheses: -(1+5(2w-1)), so:

1+5(2w-1)

determiningTheFunctionDomain
5(2w-1)+1

We multiply parentheses

10w-5+1

We add all the numbers together, and all the variables

10w-4

Back to the equation:

-(10w-4)



We add all the numbers together, and all the variables

-(10w-4)+4=0

We get rid of parentheses

-10w+4+4=0

We add all the numbers together, and all the variables

-10w+8=0

We move all terms containing w to the left, all other terms to the right

-10w=-8

w=-8/-10

w=4/5

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