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6(x+4)=-6(2x-2)+2x
We move all terms to the left:
6(x+4)-(-6(2x-2)+2x)=0
We multiply parentheses
6x-(-6(2x-2)+2x)+24=0
We calculate terms in parentheses: -(-6(2x-2)+2x), so:We get rid of parentheses
-6(2x-2)+2x
We add all the numbers together, and all the variables
2x-6(2x-2)
We multiply parentheses
2x-12x+12
We add all the numbers together, and all the variables
-10x+12
Back to the equation:
-(-10x+12)
6x+10x-12+24=0
We add all the numbers together, and all the variables
16x+12=0
We move all terms containing x to the left, all other terms to the right
16x=-12
x=-12/16
x=-3/4
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