2*(3x+6)+8=10*(7x-1)-49

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Solution for 2*(3x+6)+8=10*(7x-1)-49 equation: 



2(3x+6)+8=10(7x-1)-49

We move all terms to the left:

2(3x+6)+8-(10(7x-1)-49)=0

We multiply parentheses

6x-(10(7x-1)-49)+12+8=0



We calculate terms in parentheses: -(10(7x-1)-49), so:

10(7x-1)-49

We multiply parentheses

70x-10-49

We add all the numbers together, and all the variables

70x-59

Back to the equation:

-(70x-59)



We add all the numbers together, and all the variables

6x-(70x-59)+20=0

We get rid of parentheses

6x-70x+59+20=0

We add all the numbers together, and all the variables

-64x+79=0

We move all terms containing x to the left, all other terms to the right

-64x=-79

x=-79/-64

x=1+15/64

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