-2(4a+3)-5(2-2)=3(2a+3)-7

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Solution for -2(4a+3)-5(2-2)=3(2a+3)-7 equation: 



-2(4a+3)-5(2-2)=3(2a+3)-7

We move all terms to the left:

-2(4a+3)-5(2-2)-(3(2a+3)-7)=0

We add all the numbers together, and all the variables

-2(4a+3)-(3(2a+3)-7)-50=0

We multiply parentheses

-8a-(3(2a+3)-7)-6-50=0



We calculate terms in parentheses: -(3(2a+3)-7), so:

3(2a+3)-7

We multiply parentheses

6a+9-7

We add all the numbers together, and all the variables

6a+2

Back to the equation:

-(6a+2)



We add all the numbers together, and all the variables

-8a-(6a+2)-56=0

We get rid of parentheses

-8a-6a-2-56=0

We add all the numbers together, and all the variables

-14a-58=0

We move all terms containing a to the left, all other terms to the right

-14a=58

a=58/-14

a=-4+1/7

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