-2(3x2)=-2

Solution for -2(3x2)=-2 equation:

-2(3x^2)=-2

We move all terms to the left:

-2(3x^2)-(-2)=0

We add all the numbers together, and all the variables

-23x^2+2=0

a = -23; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-23)·2
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{46}}{2*-23}=\frac{0-2\sqrt{46}}{-46}
=-\frac{2\sqrt{46}}{-46}
=-\frac{\sqrt{46}}{-23}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{46}}{2*-23}=\frac{0+2\sqrt{46}}{-46}
=\frac{2\sqrt{46}}{-46}
=\frac{\sqrt{46}}{-23}
$