12+4n=4(n-3)

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Solution for 12+4n=4(n-3) equation: 



12+4n=4(n-3)

We move all terms to the left:

12+4n-(4(n-3))=0



We calculate terms in parentheses: -(4(n-3)), so:

4(n-3)

We multiply parentheses

4n-12

Back to the equation:

-(4n-12)



We get rid of parentheses

4n-4n+12+12=0

We add all the numbers together, and all the variables

24!=0

There is no solution for this equation

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