-2(2+2)=2v-2+2(2v+6)

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Solution for -2(2+2)=2v-2+2(2v+6) equation: 



-2(2+2)=2v-2+2(2v+6)

We move all terms to the left:

-2(2+2)-(2v-2+2(2v+6))=0

We add all the numbers together, and all the variables

-(2v-2+2(2v+6))-24=0



We calculate terms in parentheses: -(2v-2+2(2v+6)), so:

2v-2+2(2v+6)

determiningTheFunctionDomain
2v+2(2v+6)-2

We multiply parentheses

2v+4v+12-2

We add all the numbers together, and all the variables

6v+10

Back to the equation:

-(6v+10)



We get rid of parentheses

-6v-10-24=0

We add all the numbers together, and all the variables

-6v-34=0

We move all terms containing v to the left, all other terms to the right

-6v=34

v=34/-6

v=-5+2/3

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