H(x)=(5x-3)+(2-x)

Solution for H(x)=(5x-3)+(2-x) equation:

(H)=(5H-3)+(2-H)

We move all terms to the left:

(H)-((5H-3)+(2-H))=0

We add all the numbers together, and all the variables

H-((5H-3)+(-1H+2))=0


We calculate terms in parentheses: -((5H-3)+(-1H+2)), so:

(5H-3)+(-1H+2)

We get rid of parentheses

5H-1H-3+2

We add all the numbers together, and all the variables

4H-1

Back to the equation:

-(4H-1)


We get rid of parentheses

H-4H+1=0

We add all the numbers together, and all the variables

-3H+1=0

We move all terms containing H to the left, all other terms to the right

-3H=-1

H=-1/-3

H=1/3