3(v+2)=-2(6v-9)+7v

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Solution for 3(v+2)=-2(6v-9)+7v equation: 



3(v+2)=-2(6v-9)+7v

We move all terms to the left:

3(v+2)-(-2(6v-9)+7v)=0

We multiply parentheses

3v-(-2(6v-9)+7v)+6=0



We calculate terms in parentheses: -(-2(6v-9)+7v), so:

-2(6v-9)+7v

We add all the numbers together, and all the variables

7v-2(6v-9)

We multiply parentheses

7v-12v+18

We add all the numbers together, and all the variables

-5v+18

Back to the equation:

-(-5v+18)



We get rid of parentheses

3v+5v-18+6=0

We add all the numbers together, and all the variables

8v-12=0

We move all terms containing v to the left, all other terms to the right

8v=12

v=12/8

v=1+1/2

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