-12x+2(4x-2)+4=6x-3(4x-4)+20

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Solution for -12x+2(4x-2)+4=6x-3(4x-4)+20 equation: 



-12x+2(4x-2)+4=6x-3(4x-4)+20

We move all terms to the left:

-12x+2(4x-2)+4-(6x-3(4x-4)+20)=0

We multiply parentheses

-12x+8x-(6x-3(4x-4)+20)-4+4=0



We calculate terms in parentheses: -(6x-3(4x-4)+20), so:

6x-3(4x-4)+20

We multiply parentheses

6x-12x+12+20

We add all the numbers together, and all the variables

-6x+32

Back to the equation:

-(-6x+32)



We add all the numbers together, and all the variables

-4x-(-6x+32)=0

We get rid of parentheses

-4x+6x-32=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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