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-3x-12+6x=2(x-2)
We move all terms to the left:
-3x-12+6x-(2(x-2))=0
We add all the numbers together, and all the variables
3x-(2(x-2))-12=0
We calculate terms in parentheses: -(2(x-2)), so:We get rid of parentheses
2(x-2)
We multiply parentheses
2x-4
Back to the equation:
-(2x-4)
3x-2x+4-12=0
We add all the numbers together, and all the variables
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8
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