4(k-2)=6(k+2)

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Solution for 4(k-2)=6(k+2) equation: 



4(k-2)=6(k+2)

We move all terms to the left:

4(k-2)-(6(k+2))=0

We multiply parentheses

4k-(6(k+2))-8=0



We calculate terms in parentheses: -(6(k+2)), so:

6(k+2)

We multiply parentheses

6k+12

Back to the equation:

-(6k+12)



We get rid of parentheses

4k-6k-12-8=0

We add all the numbers together, and all the variables

-2k-20=0

We move all terms containing k to the left, all other terms to the right

-2k=20

k=20/-2

k=-10

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