7a+8-2a=3(2a+1)+a-5

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Solution for 7a+8-2a=3(2a+1)+a-5 equation: 



7a+8-2a=3(2a+1)+a-5

We move all terms to the left:

7a+8-2a-(3(2a+1)+a-5)=0

We add all the numbers together, and all the variables

5a-(3(2a+1)+a-5)+8=0



We calculate terms in parentheses: -(3(2a+1)+a-5), so:

3(2a+1)+a-5

We add all the numbers together, and all the variables

a+3(2a+1)-5

We multiply parentheses

a+6a+3-5

We add all the numbers together, and all the variables

7a-2

Back to the equation:

-(7a-2)



We get rid of parentheses

5a-7a+2+8=0

We add all the numbers together, and all the variables

-2a+10=0

We move all terms containing a to the left, all other terms to the right

-2a=-10

a=-10/-2

a=+5

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