-10(x+1)+5(3x-3)=4(x-3)+14

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Solution for -10(x+1)+5(3x-3)=4(x-3)+14 equation: 



-10(x+1)+5(3x-3)=4(x-3)+14

We move all terms to the left:

-10(x+1)+5(3x-3)-(4(x-3)+14)=0

We multiply parentheses

-10x+15x-(4(x-3)+14)-10-15=0



We calculate terms in parentheses: -(4(x-3)+14), so:

4(x-3)+14

We multiply parentheses

4x-12+14

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

5x-(4x+2)-25=0

We get rid of parentheses

5x-4x-2-25=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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