(2x+1)(x-1)=(x-5)(2x-5)

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Solution for (2x+1)(x-1)=(x-5)(2x-5) equation: 



(2x+1)(x-1)=(x-5)(2x-5)

We move all terms to the left:

(2x+1)(x-1)-((x-5)(2x-5))=0

We multiply parentheses ..

(+2x^2-2x+x-1)-((x-5)(2x-5))=0



We calculate terms in parentheses: -((x-5)(2x-5)), so:

(x-5)(2x-5)

We multiply parentheses ..

(+2x^2-5x-10x+25)

We get rid of parentheses

2x^2-5x-10x+25

We add all the numbers together, and all the variables

2x^2-15x+25

Back to the equation:

-(2x^2-15x+25)



We get rid of parentheses

2x^2-2x^2-2x+x+15x-1-25=0

We add all the numbers together, and all the variables

14x-26=0

We move all terms containing x to the left, all other terms to the right

14x=26

x=26/14

x=1+6/7

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