-14(z+2)+5(4z-7)=(z-4)+14

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Solution for -14(z+2)+5(4z-7)=(z-4)+14 equation: 



-14(z+2)+5(4z-7)=(z-4)+14

We move all terms to the left:

-14(z+2)+5(4z-7)-((z-4)+14)=0

We multiply parentheses

-14z+20z-((z-4)+14)-28-35=0



We calculate terms in parentheses: -((z-4)+14), so:

(z-4)+14

We get rid of parentheses

z-4+14

We add all the numbers together, and all the variables

z+10

Back to the equation:

-(z+10)



We add all the numbers together, and all the variables

6z-(z+10)-63=0

We get rid of parentheses

6z-z-10-63=0

We add all the numbers together, and all the variables

5z-73=0

We move all terms containing z to the left, all other terms to the right

5z=73

z=73/5

z=14+3/5

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