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-1/8x=-4x=
We move all terms to the left:
-1/8x-(-4x)=0
Domain of the equation: 8x!=0We get rid of parentheses
x!=0/8
x!=0
x∈R
-1/8x+4x=0
We multiply all the terms by the denominator
4x*8x-1=0
Wy multiply elements
32x^2-1=0
a = 32; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·32·(-1)
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{2}}{2*32}=\frac{0-8\sqrt{2}}{64} =-\frac{8\sqrt{2}}{64} =-\frac{\sqrt{2}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{2}}{2*32}=\frac{0+8\sqrt{2}}{64} =\frac{8\sqrt{2}}{64} =\frac{\sqrt{2}}{8} $
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