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4y(-1y+2)+4y=12
We move all terms to the left:
4y(-1y+2)+4y-(12)=0
We add all the numbers together, and all the variables
4y+4y(-1y+2)-12=0
We multiply parentheses
-4y^2+4y+8y-12=0
We add all the numbers together, and all the variables
-4y^2+12y-12=0
a = -4; b = 12; c = -12;
Δ = b2-4ac
Δ = 122-4·(-4)·(-12)
Δ = -48
Delta is less than zero, so there is no solution for the equation
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