-4y(-1y+2)+4y=12

Solution for -4y(-1y+2)+4y=12 equation:

-4y(-1y+2)+4y=12

We move all terms to the left:

-4y(-1y+2)+4y-(12)=0

We add all the numbers together, and all the variables

4y-4y(-1y+2)-12=0

We multiply parentheses

4y^2+4y-8y-12=0

We add all the numbers together, and all the variables

4y^2-4y-12=0

a = 4; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·4·(-12)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{13}}{2*4}=\frac{4-4\sqrt{13}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{13}}{2*4}=\frac{4+4\sqrt{13}}{8}
$