-1/5(x-10)=2/5(25+x)

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Solution for -1/5(x-10)=2/5(25+x) equation: 



-1/5(x-10)=2/5(25+x)

We move all terms to the left:

-1/5(x-10)-(2/5(25+x))=0



Domain of the equation: 5(x-10)!=0

x∈R





Domain of the equation: 5(25+x))!=0

x∈R



We add all the numbers together, and all the variables

-1/5(x-10)-(2/5(x+25))=0

We calculate fractions


(-5xx/(5(x-10)*5(x+25)))+(-10xx/(5(x-10)*5(x+25)))=0



We calculate terms in parentheses: +(-5xx/(5(x-10)*5(x+25))), so:

-5xx/(5(x-10)*5(x+25))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)





We calculate terms in parentheses: +(-10xx/(5(x-10)*5(x+25))), so:

-10xx/(5(x-10)*5(x+25))

We multiply all the terms by the denominator


-10xx

Back to the equation:

+(-10xx)



We get rid of parentheses

-5xx-10xx=0

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