16t(8-1t)=0

Solution for 16t(8-1t)=0 equation:

16t(8-1t)=0

We add all the numbers together, and all the variables

16t(-1t+8)=0

We multiply parentheses

-16t^2+128t=0

a = -16; b = 128; c = 0;
Δ = b2-4ac
Δ = 1282-4·(-16)·0
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-128}{2*-16}=\frac{-256}{-32}
=+8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+128}{2*-16}=\frac{0}{-32}
=0
$