(3y+10)+4y=115

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Solution for (3y+10)+4y=115 equation: 



(3y+10)+4y=115

We move all terms to the left:

(3y+10)+4y-(115)=0

We add all the numbers together, and all the variables

4y+(3y+10)-115=0

We get rid of parentheses

4y+3y+10-115=0

We add all the numbers together, and all the variables

7y-105=0

We move all terms containing y to the left, all other terms to the right

7y=105

y=105/7

y=15

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