-1/3(4-b)=1/7b

Solution for -1/3(4-b)=1/7b equation:

-1/3(4-b)=1/7b

We move all terms to the left:

-1/3(4-b)-(1/7b)=0


Domain of the equation: 3(4-b)!=0

b∈R



Domain of the equation: 7b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-1/3(-1b+4)-(+1/7b)=0

We get rid of parentheses

-1/3(-1b+4)-1/7b=0

We calculate fractions


(-7b)/(-21b^2+84b)+(-3b(-)/(-21b^2+84b)=0


We calculate terms in parentheses: +(-3b(-)/(-21b^2+84b), so:

-3b(-)/(-21b^2+84b

We add all the numbers together, and all the variables

-3b0/(-21b^2+84b

We multiply all the terms by the denominator


-3b0

We add all the numbers together, and all the variables

-3b

Back to the equation:

+(-3b)


We get rid of parentheses

(-7b)/(-21b^2+84b)-3b=0

We multiply all the terms by the denominator


-3b*(-21b^2+84b)+(-7b)=0

We multiply parentheses

63b^3-252b^2+(-7b)=0

We get rid of parentheses

63b^3-252b^2-7b=0

We do not support ebpression: b^3