0.2(x+1)0.5X=-0.3(x-4)

Solution for 0.2(x+1)0.5X=-0.3(x-4) equation:

0.2(x+1)0.5x=-0.3(x-4)

We move all terms to the left:

0.2(x+1)0.5x-(-0.3(x-4))=0

We multiply parentheses

0x^2+0x-(-0.3(x-4))=0


We calculate terms in parentheses: -(-0.3(x-4)), so:

-0.3(x-4)

We multiply parentheses

-0.3x+1.2

Back to the equation:

-(-0.3x+1.2)


We add all the numbers together, and all the variables

x^2+x-(-0.3x+1.2)=0

We get rid of parentheses

x^2+x+0.3x-1.2=0

We add all the numbers together, and all the variables

x^2+1.3x-1.2=0

a = 1; b = 1.3; c = -1.2;
Δ = b2-4ac
Δ = 1.32-4·1·(-1.2)
Δ = 6.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.3)-\sqrt{6.49}}{2*1}=\frac{-1.3-\sqrt{6.49}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.3)+\sqrt{6.49}}{2*1}=\frac{-1.3+\sqrt{6.49}}{2}
$