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(15/4y+15)y=120
We move all terms to the left:
(15/4y+15)y-(120)=0
Domain of the equation: 4y+15)y!=0We multiply parentheses
y∈R
15y^2+15y-120=0
a = 15; b = 15; c = -120;
Δ = b2-4ac
Δ = 152-4·15·(-120)
Δ = 7425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7425}=\sqrt{225*33}=\sqrt{225}*\sqrt{33}=15\sqrt{33}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15\sqrt{33}}{2*15}=\frac{-15-15\sqrt{33}}{30} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15\sqrt{33}}{2*15}=\frac{-15+15\sqrt{33}}{30} $
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