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-1/2(t+3)-10=6.5
We move all terms to the left:
-1/2(t+3)-10-(6.5)=0
Domain of the equation: 2(t+3)!=0We add all the numbers together, and all the variables
t∈R
-1/2(t+3)-16.5=0
We multiply all the terms by the denominator
-(16.5)*2(t+3)-1=0
We move all terms containing t to the left, all other terms to the right
-(16.5)*2(t+3)=1
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