-1/12m+1/3=1/4m

Solution for -1/12m+1/3=1/4m equation:

-1/12m+1/3=1/4m

We move all terms to the left:

-1/12m+1/3-(1/4m)=0


Domain of the equation: 12m!=0

m!=0/12

m!=0

m∈R



Domain of the equation: 4m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

-1/12m-(+1/4m)+1/3=0

We get rid of parentheses

-1/12m-1/4m+1/3=0

We calculate fractions


192m^2/432m^2+(-36m)/432m^2+(-108m)/432m^2=0

We multiply all the terms by the denominator


192m^2+(-36m)+(-108m)=0

We get rid of parentheses

192m^2-36m-108m=0

We add all the numbers together, and all the variables

192m^2-144m=0

a = 192; b = -144; c = 0;
Δ = b2-4ac
Δ = -1442-4·192·0
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-144}{2*192}=\frac{0}{384}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+144}{2*192}=\frac{288}{384}
=3/4
$