12y=5(y-6)-2

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Solution for 12y=5(y-6)-2 equation:



12y=5(y-6)-2
We move all terms to the left:
12y-(5(y-6)-2)=0
We calculate terms in parentheses: -(5(y-6)-2), so:
5(y-6)-2
We multiply parentheses
5y-30-2
We add all the numbers together, and all the variables
5y-32
Back to the equation:
-(5y-32)
We get rid of parentheses
12y-5y+32=0
We add all the numbers together, and all the variables
7y+32=0
We move all terms containing y to the left, all other terms to the right
7y=-32
y=-32/7
y=-4+4/7

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