1/8(16y+24)-9=-1/3(3y-27)

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Solution for 1/8(16y+24)-9=-1/3(3y-27) equation: 



1/8(16y+24)-9=-1/3(3y-27)

We move all terms to the left:

1/8(16y+24)-9-(-1/3(3y-27))=0



Domain of the equation: 8(16y+24)!=0

y∈R





Domain of the equation: 3(3y-27))!=0

y∈R



We calculate fractions


(3y3/(8(16y+24)*3(3y-27)))+(-(-8y1)/(8(16y+24)*3(3y-27)))-9=0



We calculate terms in parentheses: +(3y3/(8(16y+24)*3(3y-27))), so:

3y3/(8(16y+24)*3(3y-27))

We multiply all the terms by the denominator


3y3

We add all the numbers together, and all the variables

3y^3

We do not support eypression: y^3

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