-1+4(6x+3)=1/2(-10x-10)-5

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Solution for -1+4(6x+3)=1/2(-10x-10)-5 equation: 



-1+4(6x+3)=1/2(-10x-10)-5

We move all terms to the left:

-1+4(6x+3)-(1/2(-10x-10)-5)=0



Domain of the equation: 2(-10x-10)-5)!=0

x∈R



We multiply parentheses

24x-(1/2(-10x-10)-5)+12-1=0

We multiply all the terms by the denominator


24x*2(-10x-10)+12*2(-10x-10)-10x-5)-(1-5)-1*2(-10)-5)=0

We add all the numbers together, and all the variables

24x*2(-10x-10)+12*2(-10x-10)-10x-5)-(-4)-1*2(-10)-5)=0

We add all the numbers together, and all the variables

-10x+24x*2(-10x-10)+12*2(-10x-10)=0

Wy multiply elements

48x^2(-+24x(--10x=0

We use the square of the difference formula

48x^2(-24x(+10x=0

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