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1/2(y+2)=y+4
We move all terms to the left:
1/2(y+2)-(y+4)=0
Domain of the equation: 2(y+2)!=0We get rid of parentheses
y∈R
1/2(y+2)-y-4=0
We multiply all the terms by the denominator
-y*2(y+2)-4*2(y+2)+1=0
Wy multiply elements
-2y^2(y-8y(y+1=0
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