6(2x-8)-7=6(x-3)+5

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Solution for 6(2x-8)-7=6(x-3)+5 equation: 



6(2x-8)-7=6(x-3)+5

We move all terms to the left:

6(2x-8)-7-(6(x-3)+5)=0

We multiply parentheses

12x-(6(x-3)+5)-48-7=0



We calculate terms in parentheses: -(6(x-3)+5), so:

6(x-3)+5

We multiply parentheses

6x-18+5

We add all the numbers together, and all the variables

6x-13

Back to the equation:

-(6x-13)



We add all the numbers together, and all the variables

12x-(6x-13)-55=0

We get rid of parentheses

12x-6x+13-55=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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