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-0.0001x^2+0.024x=0
a = -0.0001; b = 0.024; c = 0;
Δ = b2-4ac
Δ = 0.0242-4·(-0.0001)·0
Δ = 0.000576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.024)-\sqrt{0.000576}}{2*-0.0001}=\frac{-0.024-\sqrt{0.000576}}{-0.0002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.024)+\sqrt{0.000576}}{2*-0.0001}=\frac{-0.024+\sqrt{0.000576}}{-0.0002} $
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