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-.3x-.18x(300-x)=63
We move all terms to the left:
-.3x-.18x(300-x)-(63)=0
We add all the numbers together, and all the variables
-.3x-.18x(-1x+300)-63=0
We add all the numbers together, and all the variables
-0.3x-.18x(-1x+300)-63=0
We multiply parentheses
1x^2-0.3x-300x-63=0
We add all the numbers together, and all the variables
x^2-300.3x-63=0
a = 1; b = -300.3; c = -63;
Δ = b2-4ac
Δ = -300.32-4·1·(-63)
Δ = 90432.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300.3)-\sqrt{90432.09}}{2*1}=\frac{300.3-\sqrt{90432.09}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300.3)+\sqrt{90432.09}}{2*1}=\frac{300.3+\sqrt{90432.09}}{2} $
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