-(y+12)=2(y-3)

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Solution for -(y+12)=2(y-3) equation: 



-(y+12)=2(y-3)

We move all terms to the left:

-(y+12)-(2(y-3))=0

We get rid of parentheses

-y-(2(y-3))-12=0



We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We add all the numbers together, and all the variables

-1y-(2y-6)-12=0

We get rid of parentheses

-1y-2y+6-12=0

We add all the numbers together, and all the variables

-3y-6=0

We move all terms containing y to the left, all other terms to the right

-3y=6

y=6/-3

y=-2

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