(3x+28)=(5x+52)=(2x-10)

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Solution for (3x+28)=(5x+52)=(2x-10) equation: 



(3x+28)=(5x+52)=(2x-10)

We move all terms to the left:

(3x+28)-((5x+52))=0

We get rid of parentheses

3x-((5x+52))+28=0



We calculate terms in parentheses: -((5x+52)), so:

(5x+52)

We get rid of parentheses

5x+52

Back to the equation:

-(5x+52)



We get rid of parentheses

3x-5x-52+28=0

We add all the numbers together, and all the variables

-2x-24=0

We move all terms containing x to the left, all other terms to the right

-2x=24

x=24/-2

x=-12

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