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x+5-(5)/(6)x=10
We move all terms to the left:
x+5-(5)/(6)x-(10)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
x-5/6x-5=0
We multiply all the terms by the denominator
x*6x-5*6x-5=0
Wy multiply elements
6x^2-30x-5=0
a = 6; b = -30; c = -5;
Δ = b2-4ac
Δ = -302-4·6·(-5)
Δ = 1020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1020}=\sqrt{4*255}=\sqrt{4}*\sqrt{255}=2\sqrt{255}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{255}}{2*6}=\frac{30-2\sqrt{255}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{255}}{2*6}=\frac{30+2\sqrt{255}}{12} $
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