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12x-24+3x=1/3(x+12)+10x
We move all terms to the left:
12x-24+3x-(1/3(x+12)+10x)=0
Domain of the equation: 3(x+12)+10x)!=0We add all the numbers together, and all the variables
x∈R
15x-(1/3(x+12)+10x)-24=0
We multiply all the terms by the denominator
15x*3(x+12)+10x)-(1-24*3(x+12)+10x)=0
Wy multiply elements
45x^2(x+10x)-(1-72x(x+10x)=0
We calculate terms in parentheses: -(1-72x(x+10x), so:We add all the numbers together, and all the variables
1-72x(x+10x
determiningTheFunctionDomain -72x(x+10x+1
Back to the equation:
-(-72x(x+10x+1)
45x^2(+11x)-(-72x(11x+1)=0
We calculate terms in parentheses: -(-72x(11x+1), so:
-72x(11x+1
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-72x(11x+1
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-72x(11x+1
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-72x(11x+1
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-72x(11x+1
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