-(x+4)+2(x-5)=3(x-6)

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Solution for -(x+4)+2(x-5)=3(x-6) equation: 



-(x+4)+2(x-5)=3(x-6)

We move all terms to the left:

-(x+4)+2(x-5)-(3(x-6))=0

We multiply parentheses

-(x+4)+2x-(3(x-6))-10=0

We get rid of parentheses

-x+2x-(3(x-6))-4-10=0



We calculate terms in parentheses: -(3(x-6)), so:

3(x-6)

We multiply parentheses

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

x-(3x-18)-14=0

We get rid of parentheses

x-3x+18-14=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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