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(x)=-x2+200x-8500
We move all terms to the left:
(x)-(-x2+200x-8500)=0
We add all the numbers together, and all the variables
-(-1x^2+200x-8500)+x=0
We get rid of parentheses
1x^2-200x+x+8500=0
We add all the numbers together, and all the variables
x^2-199x+8500=0
a = 1; b = -199; c = +8500;
Δ = b2-4ac
Δ = -1992-4·1·8500
Δ = 5601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-199)-\sqrt{5601}}{2*1}=\frac{199-\sqrt{5601}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-199)+\sqrt{5601}}{2*1}=\frac{199+\sqrt{5601}}{2} $
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