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5-(x+4)=2-(x+1)
We move all terms to the left:
5-(x+4)-(2-(x+1))=0
We get rid of parentheses
-x-(2-(x+1))-4+5=0
We calculate terms in parentheses: -(2-(x+1)), so:We add all the numbers together, and all the variables
2-(x+1)
determiningTheFunctionDomain -(x+1)+2
We get rid of parentheses
-x-1+2
We add all the numbers together, and all the variables
-1x+1
Back to the equation:
-(-1x+1)
-1x-(-1x+1)+1=0
We get rid of parentheses
-1x+1x-1+1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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